In what way is equilibrium constant for the forward reaction related to that of the reversed reaction?

a

The additional of the two is expected to be one

b

The product of the two is expected to be one

c

The two equilibrium constants are identical

d

The product of the two is always greater than one

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Correct Option
b

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Discussions (15)

Azukal
3 years ago

the correct Answer is the product of the two is expected to be one .

since the equilibrium constant for the reverse or backward reaction is equal to the inverse of the equilbrium constant of the forward reaction


mathemathically

if kb is equilibrium constant of the backward reaction and kf is the equilibrium constant for the forward reaction
then

kb = 1/kf


kb × kf = 1

teebreezy101
7 years ago

Answer is B product not addition equilibrum constant for forward rxn is the reciprocal for reverse reaction!

teebreezy101
7 years ago

Answer is B product not addition

Gerald4585
10 years ago

The answer is B,the product of the two is always one,sir

Horlarwaileh
3 years ago

The past question with me here made the same mistake.Hope myschool doesnt depend on those past questions too.

Azoyenime
2 years ago

Answer: B

FGCPOR17576703
3 years ago

My school please make the necesarry changes the answer is B

jedecoco
5 years ago

B is the correct answer

s.samuel
3 years ago

Someone should explain was going on here

Abdunz
2 years ago

Please let should be B

C. The two equilibrium constants are identical.

The equilibrium constant (Kc) for a chemical reaction indicates the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium, at a given temperature and pressure.

For a reversible reaction, the equilibrium constant for the forward reaction (Kc1) is related to that of the reversed reaction (Kc2) by the following equation:

Kc2 = 1 / Kc1

This means that the equilibrium constant of the reversed reaction is the reciprocal of the equilibrium constant of the forward reaction. Therefore, the two equilibrium constants are identical except for their numerical value.

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