In which of the following is the entropy change positive?

a

H2O(I) β†’ H2O(g)

b

Cu2+(aq) + Fe(s) β†’ Fe2+(aq) + Cu(s)

c

N2(g) + 3H2(g) β†’ 2NH3(g)

d

2HCI(g) β†’ H2(g) + CI2(g)

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Correct Option
a

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Discussions (22)

P.Petraik
8 years ago

A or D now, both of them involve increase in disorderness.
Jamb deserves strokes of cane.

samsleemy
12 years ago

entropy change is the degree of disorderliness of gas.

increase in entropy change

solid -liquid-gas

therefore d. is the correct answer

Mupheedd
8 years ago

Entropy of substance in the gaseous state is larger than entropy of substance in the liquid state

therefore, the change in entropy for H2Ol->H2Og will be positive

options A is very correct

Kellydance
1 year ago

The transition from solid to gas is called sublimation, and it involves a significant increase in disorderliness.

However, the transition from liquid to gas, also known as vaporization or evaporation, involves an even greater increase in disorderliness.

This is because:

- In a solid, particles are closely packed and have a fixed position.
- In a liquid, particles are close together but are free to move past each other.
- In a gas, particles are widely spaced and are free to move in any direction.

So, the transition from liquid to gas involves a greater increase in disorderliness, as the particles gain more freedom of movement and become more randomly arranged.

This is from Ai ooo
not sure if it's correct

AbZee77
1 year ago

Please this question should be reviewed cuz the answer is A while the actual answer is D(solid - gas)

PaulOnovo2006
1 year ago

there is a mistake in the question it's should be hcl(g) it can never be a solid

nwokogift
3 years ago

a and d is super correct

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2 months ago

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2 months ago

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samsleemy
12 years ago

entropy change is the degree of disorderliness of a body.

increase in entropy change

solid -liquid-gas

therefore d. is the correct answer

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