\(MnO_2 + 2CI^- + 4H^+ → Mn^{2+} + CI_2 + 2H_2O\).
The changes in oxidation numbers when the manganese, chloride, and hydrogen ions react according to the above equation are respectively?
\(MnO_2 + 2CI^- + 4H^+ → Mn^{2+} + CI_2 + 2H_2O\). i.e \(Mn^+ O^{2-} + 2Cl^- + 4H^+\) → \(Mn^{2+} + Cl^0_2 + 2H^+ O^{2-}\)
Mn⇒2 - 4 = -2; Cl ⇒ 0 - 1 = -1; H ⇒ 1-1 = 0.
therefore, the change in the oxidation state of Mn, Cl, and H = -2, -1, and 0.
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