S₂O^2-₃ + I₂ → S₂O₆^2- + 2I^-. In reaction above, the oxidizing agent is?

S₂O₃^2-

I₂

S₄O₆^2-

I^-

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Anzyumoh

4 years ago

I2 gains 2 electrons. An oxidising agent gains an electron, thereby reducing itself. so B is valid

note: oxidation in term of electron transfer means an increase in oxidation number (i.e loss of electron -e, to become more positive). and reduction, the decrease in oxidation number.