MnO^-₄ + 8H⁺ + ne → Mn⁺⁺ + 4H₂O. Which is the value of n in the reaction above?

Fearless7777

1 year ago

we are calculating for the charges,both for the reactant and the product
MnO4^_ is -1
8H+ is 8*1which is 8
for the product side Mn2+ is 2
and 4H2O which has no charge so 4*0 is 0
reactant 8-1=product 2
7&2
next we find the differences which is 5
so the value of n=5
ne5+

dominionCJ

6 years ago

but seven its not in the combination naa

majik2013

11 years ago

But the 7 did not appeal on the question

De sage

1 year ago

it's correct guys
8-1=7
7+ x=+2( on the other side)
x=2-7=5 .
therefore the ions are balanced

Ayoolamarvellous

3 years ago

I think the answer is wrong

Edefua

1 year ago

I'm not g'ing it

Isaac.Newton

11 years ago

Still wrong self....-1 + 8 .=7 left side