An iron ore is known to contain 70.0% Fe2O3. The obtain from 80kg of the ore is?
(Fe = 56, O = 16)
A.
35.0 kg
B.
39.2 kg
C.
70.0 kg
D.
78.4 kg
Correct Answer: Option B
Explanation
2Fe2O3 → 4Fe + 3O2
320g 224g 96g
(70) / (100) x (80) / (1) 56g
if 0.32kg of Fe293 contains 0.224 kg
Then 56kg will contain (56 x 0.224) / (0.32) =39.2 kg
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