0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution.
Calculate the number of moles of nickel that will be deposited by 0.4 faraday?

(Ni = 58.7)

olyezema

4 years ago

0.1 ---------2.95
0.4 -------- 0.4×2.95/0.1=11.8g
n=m/M
n = 11.8/58.2 = 0.20moles

Anela

1 year ago

m=2.95
mm=58.7
(Let's say f1 and f2)
f1=0.1
f2=0.4

n=2.95/58.7
=0.0503

Recall we're asked to find the no. of moles for 0.4f

0.1 - 0.0503
0.4 - x

=0.4×0.0503/0.1
=0.20

Williamsdamilare9

3 years ago

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