What volume of 11.0 M hydrochloric acid must be dilute to obtain 1 dm3 of 0.05 M acid?

Federal123

4 years ago

I'm having 0.0045… ≈0.005

C1V1=C2V2
Using that equation

I think the answer isn't there😔

Alisha101

2 years ago

From my understanding M1V1=M2V2
Therefore,1*0.05=11*x
x=0.05/11=0.0045
But we were asked to find what volume must be added therefore u would easily subtract to get the volume 0.05-0.0045=0.0455 approximately 0.05dm3
I hope it helps

Preye24

2 years ago

The 11M is wrong, its meant to be 1.0M
therefore it'll be ;
C1÷V1 =C2 ÷V2
1.0M ÷ 1dm³ =0.05M ÷ V2
if u cross multiple, you'll have
V2 = 0.05M ×1 dm³÷ 1M
V2= 0.05dm³
option A. 0.05dm³ is correct

Joy091

3 years ago

using dilution formular=> C1V1=C2V2
C1=11.0, C2=1, V1=? V2=0.05

11.0×V1=0.05
V1= 0.05/11.0
V1=0.0045dm³= 4.5cm³
no correct option

UcheG

5 years ago

Peradventure the conc of the acid initially was 1.1M and not 11M

King_goodness

2 years ago

It is either there is a mistake in the question or there is no answer

Magbert

3 years ago

see ehh🥷
That 11.0 M is wrong it's meant to be 1.0M ‍♂️‍♂️
Then with 1.0M u will get option A as the ans .

deymolah

9 years ago

i dont know how they got it gan sef

promisedare123

9 years ago

abeg make person post explanation. I no dey get am

Eaglelife

1 year ago

There is an answer just subtract the answer from the volume

Gobbler

9 years ago

Use c1v2=c2v2

HCl+H2O -> H3O^+ +Cl

:. 11*x = 0.05*1

x = 0.05/11

=0.045 ~ 0.05