What is the concentration of H⁺ ions in moles per dm³ of a sodium of pH 4.398?

Charlieboy2018

6 years ago

PH=-Log10[H+] i.e PH=1/log10[H+]
BUT remember acid ,base,salt.
H+=10^PH.
H+=10^4.398=0.00003999=4.0*10^-5

Parkzih

2 years ago

Yes, the correct answer is A: 4.0×10^-5
Solution:
PH= -log [H+]
4.398= -log [H+]
H+ = antilog [ -4.398]
= 3.9× 10^-5
= approximately; 4.0×10^-5

FGCPOR17576703

3 years ago

How would you do this without calculator for goodness sake?

CBA

7 years ago

How is this possible for use to solve this using jamb calculator?

Gobbler

9 years ago

Abeg my school explain better because we don't get it

olyezema

4 years ago

since pH=-log10[H+],
we have 4.398 = -log10[H+],
: . log10[H+] = -4.398 = -5.0+0.61= 5.61
: . [H+] = antilog 5.61
= 4×10-⁴moldm-³
New school chemistry page 105

Ademary222

8 months ago

l love this test
thanks Soo much for the consideration

fairlycute583

10 years ago

me too pls don't get it

vizzini2

11 years ago

uhhhh......wtf is that ......dunt get

Kadyboy95

12 years ago

pls expanciate cos i dont get it...

PET10

12 years ago

I disagree wit dat ans..... Plss. Explain

DEkeeper1

2 months ago

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DEkeeper1

2 months ago

hi

Elly anna

10 years ago

Yea really dnt get dat