Equal volumes of CO,SO2, NO2 and H2S were released into a room at the same point and time. Which of the following gives the order of diffusion of the gases to the opposite corner of the room?
(S = 32, C = 12, O = 16, N = 14, H = 1)

Anobimuhammed

7 years ago

Note This: The Higher The Relative Molecular Mass The Lower The Rate Of Diffusion And Vice-versa.
Meaning That,let's Consider This
Relative Molecular Mass Of:
CO=12+16=28
SO2=32+16*2=32+32=64
H2S=1*2+32=2+32=34
NO2=14+16*2=14+32=46
Order Of Diffusion Are=CO,H2S,NO2,SO2

Doclord

3 years ago

Nice one my school👌👌👌👌👌👌👌

Dinachi1

2 months ago

why can't it be the other way round.
They didn't specify if it was in increasing or reducing order

daaniiel

8 years ago

Mr admin pls explain dis question

okiks1999

5 years ago

The option are not correct and the question is not complete