one isomer
two isomers
three isomers
four isomers
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Discussions (34)

Using this formula 2^(n-4) 1
where n= no. Of carbon
2^(5-4) 1
= 2^1 1
= 2 1
= 3
therefore we have 3 isomers

u are all wrong the question is talking of cycloalkanes isomers...it is 4...
refe4ence pg 236 of the lamlards

It's 3 ooo, this website is a deceiver, just use this isomers formula 2 raise power n-4 then +1

My school, please do the correction because it has not been corrected so far. It's option C

The answer is 4
cyclopentane
1-methylcyclobutane
1-ethylcyclopropane
1,2-diethylcyclopropane

Option D is the correct answer.
Even with the formula 2^(n-4)+1, the result will still give 4.
Therefore the number of isomers for the cycloalkane C5H10 is 4






