Cr\(_2\)O\(_7\)\(^{2-}\) + 6Fe\(^{2+}\) + 14H\(^+\) → 2Cr\(^{3+}\) +6Fe\(^{3+}\) + 7H\(_2\)O. In the above , the oxidation number of chromium changed from?
a
+7 to +3
b
+6 to +3
c
+5 to +3
d
-2 to +3
Explanation
Correct Option
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Undefeated.123
6 years ago
First we find the oxidation num of Cr2O7
X+2+(-2×7)
2x+14
2x/14=7
Then we say that the charge of 2CR3+ is +3.
+7 to +3









