Cr\(_2\)O\(_7\)\(^{2-}\) + 6Fe\(^{2+}\) + 14H\(^+\) → 2Cr\(^{3+}\) +6Fe\(^{3+}\) + 7H\(_2\)O. In the above , the oxidation number of chromium changed from?

a

+7 to +3

b

+6 to +3

c

+5 to +3

d

-2 to +3

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Explanation

Correct Option
b

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Discussions (18)

Undefeated.123
6 years ago

First we find the oxidation num of Cr2O7
X+2+(-2×7)
2x+14
2x/14=7
Then we say that the charge of 2CR3+ is +3.
+7 to +3

NS XY
11 years ago

dia is no answer dan A

godwayne
12 years ago

the correct ans is A

France
12 years ago

Answer is A. +7 to+3

nkpresh
11 years ago

the answer is A

Bola148
12 years ago

Yes @ matins, they ar jst confusn pple

Myschool Paul
10 years ago

Thanks for your contributions. Correction has been made.

John olugbenga
12 years ago

Pls stop all dis confusion...d ans is A

Darasimi779
3 years ago

You can never know the value of a thing until you lose it.😒😒😒😒😒

Evans lds
12 years ago

I feel they were sleeping while pasting their ans

Martins patrick
12 years ago

most of ur ans are wrong

Azabol98
4 months ago

The answer is +6 and +3

Guitarido
7 years ago

D

rherbeea
1 year ago

explanation for the preparation of NaOH

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