Correct Answer: Option A

Explanation

To determine the formula of the oxide, let's analyze the given information:

    Stoichiometrically, 2 X   +  3/2 O\(_2\)  →  Oxide

Given :

1. 1 litre of monoatomic gas X combines with 1.5 litres of an oxide.

2. The reaction is a combination reaction, where X reacts with oxygen to form an oxide.

If the atom of the elements are                 X                     and                O\(_2\)

Reacted volumes were given as             1dm\(^3\)                              1.5dm\(^3\)

Stoichiometrically, moles of molecules   2 moles                                3 moles

X(monoatomic) and oxygen(diatomic)    2 x 1                                 3 x 2 = 6 (3 moles of O\(_2\) = 6 oxygen atoms)

Divide ratios by 2                                    \(\frac{2}{2}\)                           \(\frac{6}{2}\)

The formula ratio :                                     1                       :                   3

Therefore, the formula of the oxide is XO\(_3\)

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