10cm3 of CO is mixed and sparked with 100cm3 of air containing 21% O2. If all the volumes measured at S.T.P. the volume of resulting gases would be?

kitana100

7 years ago

Volume of air = 100cm^3
Percentage of oxygen in air = 21%
Actual volume of oxygen = (21/100) x 100
= 21cm^3
Remaining components of air that do not react = Volume of air - Volume of oxygen
= 100-21
= 79 (made up of nitrogen, carbon (IV) oxide, water vapour and noble gases)
At s.t.p., carbon (II) oxide, oxygen and carbon (IV) oxide are all gases. So, the equation of reaction is:

2CO(g) + O2(g) ---> 2CO2(g)
2vol 1vol 2vol
Before sparking 10cm^3 21cm^3 -
On sparking 10cm^3 5cm^3 10cm^3
After sparking 0cm^3 16cm^3 10cm^3
Total volume of resulting gas = Volume of excess oxygen + Volume of CO2 produced + Volume of unreactive components of air
= 16cm^3+ 10cm^3 + 79cm^3
= 105cm^3

tyjesma

11 years ago

21% of O2 in 100cm³ of Air =21%/100% x 100 = 21...10cm³ of CO2 reacts With 5cm³ of O2...10cm³ + 5cm³=10cm3...From Gay luccas law of combining volume...residual gas= 21cm³-5cm³= 16cm³..therefore resultant Gases= 16 + (100-21) + 10 =105cm³

Faitz

6 years ago

How was 5 gotten?

Opeyemi.A

3 years ago

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SymplyBecky85

4 years ago

There's no explanation for the question