A solution X on mixing with AgNO3 solution, gives a white precipitate solution in NH3. A Solution Y, when added to X, also gives a white precipiate which is soluble on boiling. Solution Y contains?
Ag+ion
Pb2+ion
Pb4+ion
Zn2+ion
Al3+ion
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Explanation:
When a solution X is mixed with AgNO3, a white precipitate is formed in NH3. This indicates that solution X contains Cl- ions. When solution Y is added to X, a white precipitate is formed which is soluble when boiled. This means that solution Y contains Pb2+ ions, as the white precipitate formed is PbCl2, which is soluble in hot water.
It is important to note that Ag+ ions would have formed a white precipitate in solution X without the need for NH3, and the resulting precipitate would not have been soluble in boiling water. Pb4+ ions do not form a white precipitate with Cl- ions, so it is not an option. Zn2+ and Al3+ ions do not form a precipitate with Cl- ions at all.
Therefore, the correct answer is Option B: Pb2+ ion.
When solution X reacts with AgNO₃, a white precipitate soluble in NH₃ is formed. This confirms that X contains Cl⁻ ions, because AgCl is a white precipitate that dissolves in ammonia.
When solution Y is added to X, another white precipitate forms but dissolves on boiling. This behaviour is characteristic of lead(II) chloride (PbCl₂).
PbCl₂ is:
White
Slightly soluble in cold water
More soluble in hot water (dissolves on boiling)
This means solution Y contains Pb²⁺ ions, because Pb²⁺ + 2Cl⁻ → PbCl₂(s).
