What is the population density of Ageratum sp. of frequency 1,850 on a land area measuring 100m\(^2\)?
Given:
Total number of individuals, N = 1,850
Total Area, A = 100 m\(^2\)
Population Density = \(\frac{Total individuals}{Total Area}\)
= \(\frac{1850}{100}\)
= 18.50 plants/m\(^2\)
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