Correct Answer: Option D

Explanation

The problem states the parents are both heterozygous (Rr). When these individuals are crossed, each parent contributes one allele (R or r) to the offspring. 

Based on the Punnett Square, we count the frequency of each unique genetic combination: 

Homozygous Dominant (RR): 1 occurrence

Heterozygous (Rr): 2 occurrences

Homozygous Recessive (rr): 1 occurrence 

In Mendelian genetics, although the prompt labels the result of an Rr X Rr, crosses as the F\(_1\) this specific distribution (RR,Rr, Rr, rr) is standard for the F\(_2\),(the offspring of two F\(_1\)). Regardless of the label, the ratio of these specific results is 1∶2∶1.

There is an explanation video available below.

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