If both parents are heterozygous for a trait. the probability that an offspring will be recessive for that trait is?
1/2
1/4
1
3/4
Explanation
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The correct answer is B not A
Outcome
RR , Rr, Rr, rr
:. The probality of the recessive trait (rr) is 1/4
The answer is B
Because heterozygous means something like Rr,Tt.
Therefore
Rr*Rr gives u
RR Rr Rr rr
Then the one that has the recessive trait is 1/4
the answer is not correct cos an heterozygote mean different tall and short plant in the same positionTtwhen a two Tt ×Tt=TT,Tt,Tt,tt
so the correct answer about the recessive plant is just one short plant tt so it should be1/4
and note this and homozygote plant can be a short plant at the same position and a tall plant at the same position
so the answer is note correct
Question: if both parents are heterozygous for a trait, the probability that an offspring will be recessive for that trait is?
My suggestion: firstly, what's a recessive trait, which I know too well is gene or trait which are not effective at moment or generation but it's hidden.
So from punnett square you're having a homozygous pure gene of (TT) and (tt) and heterozygous gene of (2Tt), where the capital T is the dorminant gene and the small t is the recessive gene.
Therefore the trait having recessive trait attached to them is the (2Tt).
So shouldn't our answer be 2/4 ~ 1/2
The answer is very wrong
The correct answer is 1/4 and not 1/2
This is because a recessive Gene will only express itself in the absence of a contrasting Gene.
this ur answer is wrong my school...u have solved thesame question i think in 2010 and u got the correct answer but here u are saying another thing...ur correction pls
