Mass of a crucible = 10g,
Mass of a crucible and soil before heating =29g
Mass of a crucible and soil after heating = 18g
From the information above, determine the percentage of water in the given soil sample?
20%
25%
40%
60%
Explanation
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crucible & soil =29g
crucible & soil after heating = 18g
.'. remember when the soil was heated it lost moisture (water).
crucible & soil before heating – crucible & soil after heating = moisture loss
29g - 18g = 11g
the questions requires the percentage of water in the soil
so the mass of the soil is
crucible & soil - crucible = mass of soil
29g - 10g = 19g
percentage of water in the soil is
11/19 × 100%
= 57.89.....%
~ 60%
Percentage of water in the soil sample
=Wet weight - dry weight/dry weight × 100
Wet weight=29g
Dry weight=18g
% = 29-18/18 × 100
=11/18 × 100
=0.6111 × 100
=61.11%
≈60%
mass of soil before heating is 29-10=19
mass of soil after heating is 18-10=8
8×100/19= 42% the closest answer there is 40
