The initial volume of water poured into a bag of dry soil was 50ml and the amount that drained through was 35mI. The percentage water content of the fully soaked soil is therefore?
46.7
25.0
20.0
30.0
Explanation
Video Explanation
Post your Contribution
Discussions (8)

option D is the correct answer
intitial vol of water is 50ml,
water drianed is 35ml
therefore percentage water containt is =50-35=15
containt of water/initial vol of water =15/50x100 =0.3x100= 30%..

from the explanation given by my school the answer is supposed to be 20
50-35/50×100=-20

please the correct answer should be A
To find the percentage water content, you can use the formula:
Percentage Water Content
=
(
Amount of Water Drained
Initial Volume of Water
)
×
100
Percentage Water Content=(
Initial Volume of Water
Amount of Water Drained
)×100
Substitute the values:
Percentage Water Content
=
(
35
ml
50
ml
)
×
100
Percentage Water Content=(
50ml
35ml
)×100
Percentage Water Content=(
50
35
)×100
Percentage Water Content
=
0.7
×
100
Percentage Water Content=0.7×100
The correct answer is 70. Therefore, the correct option from your provided choices would be:
A.
46.7
%
46.7%

