A man whose blood group is heterozygous B is married to a woman whose blood up is also heterozygous B

Which of the following statements is correct about the blood group of their four offspring?

Derek644222

2 years ago

Heterozygous means two contrasting alleles located on the same position on a pair of chromosomes e.g Tt for tallness and Rr for a heterozygous red plant

Now for the this question the heterozygous pair for both the married man and woman are
Man. & woman
Bb. Bb

now crossing the two we will obtain 4 occurances
of BB, Bb, Bb & bb that is
1BB
2Bb
1bb

and remember that the both parents are heterozygous with the contrasting allele of Bb for heterozygous and not BB or bb for homozygous

now their offspring allele ratio will be 1:2:1
and 2 out of the 4 occurrances contained the heterozygous allele of the parents = Bb hence

option is correct D is correct
where by 2 of them will belong to the boood group B for the heterozygous trait of Bb

Award0001

2 years ago

myschool is correct
Heterozygous B is Bo not Bb
now if you cross
B o × Bo
BB Bo Bo oo
p.r = 3:1
G.r 1:2:1
now out of thet four children, 3 possesd the B blood group

Derek644222

2 years ago

my school please the correct answer should be D and not A

De sage

1 year ago

the correct answer is

C

Kanfechi

2 years ago

Heterozygous had an allele of Bb
hence, if you use the Pandora box method you'll have

B. ×. b
B. BB. Bb
b. Bb. bb

hence, the ratio is BB...Bb...Bb...bb...

so they have
1:2:1

and that's two heterozygous B

D is the answer
abeg