A woman who is heterozygous for the disease haemophilia marries a man who is  haemophilic. What percentage of their offspring would have the disease?

Omimi

7 years ago

let A man who is heterozygous of hemophilia be --Hh
and the woman be double recessive for the allele be hh
after a test cross
H *h -- Hh
H*h -- Hh
h*h --hh
h*h -- hh
the ratio of Hh(offsprings with hemophilia ) is 2/4
percentage =2/4×100 =50%

2277.7

7 years ago

when cross breeded the gentype is 2:2
=2/4*100
where the 2:2 is for the four offspring of the couples

Classicboymoses

3 years ago

correct answer is D

2277.7

7 years ago

answer is C 50%

Son1

2 years ago

correct answer is D but C is still somehow correct