When sickle cell carrier marries a normal woman, the probability of them having a normal offspring is
0.75
0.25
0.5
.1
Explanation
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D correct answer is C (0.5), u guys did a wrong calculation. When u pair AS to AA it wud give AA AA AS AS. Den d probability of normal offspring is 2 out of 4 (2/4)= 1/2 = 0.5
0.5 is nt correct at all.....only 1 is correct cuz dey will never av an abnormal child
AA(normal) * AS(carrier) gives
AA(normal) AS(carrier) AA(normal) and AS(carrier)
gg+gG
u cross breed
then gg, gG, gg, gG are produced.
the total number of their probability = 100
and from the above we have
2gg and 2gG
100/4=25
25*2=50 for 2gg and 2gG each.
=>50gg +50=100
50gg=100-50=50
gg=50/50=1
finally, the answer is "1"
The answer is 0.5. You see, a carrier of sickle cell is denoted as AS while a normal person is denoted as AA. When we cross the two individuals, we end up having 2 AA and 2 AS. These are the offsprings. It is easy to see that the probability of producing normal offring is 2/4=0.5
I disagree... a normal human being is AA and a carrier is AS
crossbreeding we have the genotype as AA AA AS AS
two normal and two carriers so that makes the probability 2/4 which is 0.5.. please verify... they didn't ask for ratio but probability
The carrier has a genotype of AS and the normal woman has a genotype of AA when crossed will produce AA,AA,AS,AS. All the offsprings are normal as they do not have the sickle cell disease. There are only 2 carriers and 2 non-carriers not a sickle child.
The answer should be 0.5
A normal person has the genotype AA while a carrier has a genotype AS. So if the two were crossed together, they will form two AA which is normal and two AS which is a carrier.
From the question we are asked of the probability of getting normal offspring
Therefore, the probability of getting normal offspring is 2/4 which equals 1/2 =0.5
Assuming the sickle cell carrier is AS and the normal woman AA, the mixture produces AA, AS, AA and AS.
So, 2AAs and 2ASs are the possible children but the probability is:
Pr(a normal offspring)= number of normal offsprings / total number of offsprings
Pr(normal offspring)= 2/4= 1/2= 0.5
The selected answer is wrong:
The answer is meant to be codominance as both the red and the white have effect on the phenotype.
REF: New System Biology, page 339
It seems I have understood the question. A sickle cell carrier and a normal woman marrying each other are sure to give birth to a normal child. Therefore the probability is one. Another clear evidence can be deduced from the crossing of AA(normal) and SS(sickle cell carrier) . All the offspring produced are AS, therefore their probability of giving birth to a sickle cell carrier is zero while their probability of giving birth a normal child is one (sure).
