An albino man marries a normal woman (homozygous for skin pigmentation). What is the probability that the people could have an albino child?
0%
0.5%
25%
60%
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Alright here is the explanation of it....
Albino man marries normal woman
Normal: Albino
Aa : aa
Aa : aa
Aa/aa : Aa/aa
2. : 2
Aa : aa
2 : 2
Their 2:2 which is =0%

If the male is homozygous recessive for albinism (aa) and the female is heterozygous for albinism (Aa), then each of their offspring will inherit one allele from each parent. There is a 50% chance that each offspring will inherit the recessive allele from the father and the dominant allele from the mother (Aa), and a 50% chance that they will inherit the recessive allele from both parents (aa). Therefore, all of their offspring will be carriers of the albinism gene, but only half will express the trait.
The answer is 0%
A is correct.

homozygous = AA
albino = aa cos it's recessive trait
multiply
Aa Aa Aa Aa, so none is albino as u can see all the pikin na heterozygos

