A man with heterozygous genotype for blood group B marries a woman with heterozygous A, what percentage
(%) of their children would be universal donor?

aliyah24434

2 months ago

Step 1: Understand the genotypes
Blood group B (heterozygous) = BO
Blood group A (heterozygous) = AO
Step 2: Possible gametes
Man (BO) → B or O
Woman (AO) → A or O
Step 3: Cross them (Punnett square)

A O
B. AB. BO
O. AO. OO

Step 4: Identify universal donor
Universal donor blood group = O (OO)
From the table:
AB
BO
AO
OO
Only 1 out of 4 is OO
Step 5: Convert to percentage
1/4*100=25%
Final Answer:
B. 25%

olakiiye

1 year ago

is the answer not 50%

CHRIST IS KING

5 months ago

Ab * Ab = ab, a, b, o
0 is 1 out of the 4 alleles
1/4 = 0.25
0.25 * 100 = 25%

chimmy_adela

2 years ago

?

Fayvourwrites

1 year ago

Aa Bb
AB Ab
aB ab.

so AB is 1 out of the 4.
100/4 = 25%

Fayvourwrites

1 year ago

the woman is Aa
the man is Bb
if you cross them you have...
AB Ab
aB ab
so AB which is universal donor is 1 out of the 4.
that gives 100/4 =25%