In man haemophilia is recessive and sex linked, The
probability of carrier mother and a normal father having a haemophilic male is
1/4
1/8
2/3
1/2
1
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Discussions (19)
Admin,I think the answer should be 1/4,Kindly Correct me if i'm wrong.
Carrier Mother:XA Xa
Normal Father :XA Y
Cross Breeding= XAXA XAY XaXA XaY
Sufferer Male=XaY
Ans=1/4.
The correct ans is half,since the Mother is a carrier(AS) and father is normal (AA) during test crossing the outcome are (AA,AA,AS,and AS) Probability=number of carrirer child divide by total outcome, i.e 2/4=1/2
You need to fix this problem of wrong answers. I was marked wrong yet your AI explanation even chose A as the answer. This can be very misleading to students especially if one doesn't check the discussions and decides to trust your answers
The answer (1/8) is correct. Probabilty = Pr of son x Pr of haemophilia= 1/2 x 1/4 = 1/8
if we cross-link them
X^hX^n + X^n + y^n 
X^hx + X^hy + X^nx + X^ny
so out of four children , Two are Carries hence the ratio is 2/4 —-> 1/2 
