35) When 100g of liquid L1at 78oc was mixed with 50g of another liquid of...

35) When 100g of liquid L1at 78oc was mixed with 50g of another liquid of
68oc. what is the temperature of the resulting mixtures?

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Answers (3)

Aliyu
4 weeks ago
Explanation
Heat lost by L1 = heat gained by L2

cL1 = 2cL2

100 x 2cL2 x (78 - 66)

= xg x cL2 x (66 - 50)

xg = 150g
agbojays
4 weeks ago
Heat lost by L1 = heat gained by L2

cL1 = 2cL2

100 x 2cL2 x (78 - 66)

= xg x cL2 x (66 - 50)

xg = 150g
isaaq
4 weeks ago
H=mc*change in temp. specific hit capacity of L1=1 and that of L2=1/2.
hit lost by L1=hit gain by L2 100*2*(78-60)=x*1/2*(60-50) x=1800/5=150g
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