A body which is uniformly retarded comes to rest in 5s after travelling a distance...

A body which is uniformly retarded comes to rest in 5s after travelling a distance of 10m. What is the initial velocity?

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Answers (4)

Dende
1 month ago
S=ut+½at²

20=10u + ½(v-u/t) x 10²

but v=0, hence

20=10u + ½(0-u/10) x 100

20=10u - 10u/2

find the LCM

20=5u

u=4m per second square.
Emmanuella
1 month ago
S=ut + ½at²
S=10m/s, t=5secs
a=v-u/2
V is not stated
a=10/2 =5
S=ut+½at²
10=u×5 + ½×2×5²
10=5u + 15
10-15=5u
-5=5u
u=-5/5
u=-1
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