The horizontal component of the initial speed of a particle projected at 300 to the...

The horizontal component of the initial speed of a particle projected at 300 to the horizontal is 50 ms-1. If the acceleration of free fall due to gravity is 10 ms-2, determine its
(b) Speed at maximum height reached.?

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Answers (3)

Vek Tor
1 week ago
a=0, as there is no horizontal acceleration

R=u^2sin2@/g
R=u^2/g
300=u^2/10
u^2=3000
u=square root of (3000)
u=54.8m/s
mustapha
1 week ago
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isaaq
1 week ago
(a) Let u represent the initial velocity of particle and ux the horizontal component. ux = u cos 30o = 50 u = 50 cos 30 = 57.7 ms-1 (b) Let v represent its velocity at the maximum height. ALTERNATIVELY At the maximum height v = vvx2 + vy2 vy = 0 vx = ux = 50ms-1 = v 502 + 02 = 50ms-1
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