if 4,x,y,z,64 are consecutive terms of an exponential sequence.find the value of x,y,z.?

if 4,x,y,z,64 are consecutive terms of an exponential sequence.find the value of x,y,z.?

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Answers (7)

Anuoluwa
1 month ago
x=8
y=16
z=32
Dende
1 month ago
The first term=4
The 64 given there is the 5th term by the arrangement
then a=4 i.e first term
T5=a+4d=64
4+4d=64
4d=64-4
4d=60
d=60/4=15

values of x, y, z represent T2, T3 and T4
then
T2=a+d=4+15=19
T3=a+2d=4+2(15)=4+30=34
T4=a+3d=4+3(15)=4+45=49

therefore x, y and z are respectively 19, 34 and 49

Credit : Vek Tor
virtue
1 month ago
4,x,y,z,64
a = 4 5th term = 64
given that Tn = a+[n-1]d=n
4+(5-1)d=64
4+(4)d = 64
8d = 64
d = 64/8
d = 8
x, y, z, is
T2 = 4+(2-1)4
= 4+[1]8
= 5*8= 40
T3 = 4+(3-1)8
= 4+(2)8
= 6*8
= 48
T4= 4+[4-1)8
= 4+(3)*8
= 56
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