### 1. Find the equation whose roots are -2/5 and 3/4 2. Factorise 8y^2-10y-3?

1. Find the equation whose roots are -2/5 and 3/4
2. Factorise 8y^2-10y-3?

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1. (x - 2/5)(x +3/4) = x^2 + 3/4x - 2/5x - 3/10
=x^2 +7/20x - 3/10
Multiply through by 20
=20x^2 + 7x - 6.
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1.
x=-2/5 or x=3/4
x+2/5=0 or x-3/4=0
(x+2/5)(x-3/4)=0
x(x-3/4)+2/5(x-3/4)=0
x^2-3x/4+2x/5-3/4=0
x^2-7x/20-3/4=0
multiply both sides by 20
20x^2-7x-15=0

2.
8y^2-10y+3=0
8*3=24
8y^2-6y-4y+3=0
2y(4y-3)-1(4y-3)=0
2y-1=0 or 4y-3=0
2y=1 or 4y=3
y=1/2 or 3/4
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• Chidera: I posted 8y^2-10y-3
1 month ago
(1) -2/5 & 3/4
x = -2/5 or x = 3/4
5x=-2 or 4x=3
5x+2 or 4x-3
(5x+2)or(4x-3)
20x^2-15x-8x-6=0
20x^2 - 7x - 6=0
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