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a cell of emfE and internal resistance r is connected in series with a resistor...

a cell of emfE and internal resistance r is connected in series with a resistor and an ammeter A, and current 2.1A is observed to pass when the resistance of 2ohms.
when another resistor of 5ohms is connected in parallel to the 2ohms resistor the new ammeter reading is 2.5A.
calculate the internal resistance and the emf of the cell?
In Physics
1 Answers Available
Asked by Elizabeth Awele on 4th August, 2022
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
JAMB CBT Mobile App 2024 - Free Download