Gain 200 level admission into any university - no JAMB and low fees - Call 07063900993

A man uses a rope to haul a box of weight600N up an inclined wooden...

A man uses a rope to haul a box of weight600N up an inclined wooden plank of effective length 3.0m and on platform 1.0m high. If in doing so, he exerts a force of 400N on the rope.Calculate:
(I) the frictional force between the case and the plank
(ii) the velocity ratio of the machine
(iii) the mechanical advantage
(iv) the useful work done in joules?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

Answers (1)

Dende
1 month ago
triangle 1, up
3 hypotenuse, along plank
sqrt (8) = 2 sqrt 2, horizontal

plankward component of weight = 600 [ (2/3) sqrt 2] = 566 N
slopeward component of weight = 600 (1/3) = 200 N
(1) but we pulled with 400 N so friction force = 400-200 = 200 N
(2) velocity up/ velocity along slope = 1/3
(3) pulls with 400 and lifts 600 so 6/4 = 3/2
(4) 600 N * 1 meter up = 600 Joules
Ask Your Own Question

Quick Questions

See More Physics Questions