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a sonometer wire of length 100cm under a tension of 10N, has a frequency of...

a sonometer wire of length 100cm under a tension of 10N, has a frequency of 250HZ, keeping the length of the wire constant the tension is adjusted to produce a new frequency of 350 HZ. the new tension is
a) 5.1N
b) 19.6N
c) 14.0N
d) 7.1N?

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Answers (1)

Robert
1 month ago
f= (1/2L) × √(T/M)

Where: f= frequency, L= length, T= tension and M= mass/length(mass per unit length).

Length is constant.

f= 250Hz,
T= 10N

f2= 350Hz,
T2= ?

f = (√(T))/L

L= √T/f

√T/f= √T2/f2
√10/250= √T2/350
√10/5= √T2/7
7√10/5 = √T2
T2= 49×10/25
= 49×2/5
= 98/5= 19.6

T2= 19.6N
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