A given mass of gas at 30°c is trapped in a tube if it's volume...

A given mass of gas at 30°c is trapped in a tube if it's volume is reduced to two-thirds of it's initial value by applying a pressure twice the original value calculate the new temperature?

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Answers (2)

Chinecherem
5 months ago
initial temp.=30+273=303, final temp.=x
initial volume=v, final volume=2/3
initial pressure=p, final pressure=2p
p1*v1/t1=p2*v2/t2, p*v/303=2p*2/3/x.(cross multiplication),p*v*x=303*2*2/3=404
x=404k
Holajoseph
5 months ago
404k or 131degree Celsius
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