Two helicopters A, b fly in space with velocities of Va=i+4j+3k and Vb=4i+2j-4k relative to...

Two helicopters A, b fly in space with velocities of Va=i+4j+3k and Vb=4i+2j-4k relative to a stationary observer at origin 0,0,0 if these helicopters fly at right angles to each other, their distance apart after 5s is?

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Answers (2)

AHBAM
2 months ago
AHBAM
2 months ago
displacement of a= 5(i+4j +3k)=5i+20j+15k
disp of b = 5(4i+2j-4k)=20i+10j-20k
disp apart= disp a + disp b=25i+30j-5k
distance apart =modulus of displacement=√25²+30²+5²=39.37 units
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