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3(nP2+24)=2nP2?

3(nP2+24)=2nP2?

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Answers (2)

HENRYVILLA
1 month ago
james
1 month ago
3(nP2 + 24)=2nP2
3(n!/{n-2}! +24)=2n!/(2n-2)
"#recall_that n!=n(n-1)(n-2)(n-3).....,....e.g 3!=3(3-1)(3-2)(3-3)!
=3*2*1*0!
0!=1
=3*2*1*1=6#"


3[n(n-1)(n-2)!/(n-2)! + 24]=2n(2n-1)(2n-2)!/(2n-2)!
(n-2)! cancle (n-2)!
(2n-2)! cancle (2n-2)
3[n(n-1) + 24]=2n(2n-2)
3[n2 - n + 24)=4n2 - 4n
3n2 - 3n + 72=4n2 - 4n
0=4n2 - 3n2 - 4n + 3n - 72
n2 - n - 72=0
(n2 - 8n) + (9n - 72)=0
n(n-8)+9(n-8)=0
(n-8)(n+9)=0
n-8=0 or n+9=0
n=8 or -9
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