draw a block and tackle system of pulleys with a velocity ratio of 5. A...

draw a block and tackle system of pulleys with a velocity ratio of 5. A block and tackle with a velocity ratio of 5 is used to raise a mass of 25kg through a vertical distance of 40cm at a steady rate. If the effort is equal to 60N, determine the distance moved by the effort.?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

If the block moves .40 meters then the line is pulled 5 * .4 = 2 meters (a)
the work done by the puller person on that line is
W in = 60 N * 2 meters = 120 Joules (b)
the useful work done on the block was to lift it .40 meters
work out = m g h = 25 * 9.81 * .4 = 98.1 Joules
so the loss due to friction was
120 - 98.1 = 21.9 Joules (c)
isaaq

Latest WAEC Past Questions 2020 App - Free Download - 12887

Answers (1)

isaaq
8 months ago
If the block moves .40 meters then the line is pulled 5 * .4 = 2 meters (a)
the work done by the puller person on that line is
W in = 60 N * 2 meters = 120 Joules (b)
the useful work done on the block was to lift it .40 meters
work out = m g h = 25 * 9.81 * .4 = 98.1 Joules
so the loss due to friction was
120 - 98.1 = 21.9 Joules (c)
Ask Your Own Question

Quick Questions

See More Physics Questions
 
Latest WAEC Past Questions 2020 App - Free Download - 12887