A spring stresses by 15cm when a mass of 300g is hang down from it,...

A spring stresses by 15cm when a mass of 300g is hang down from it, if the spring is then string is stressed additional 10cm amd released, calculate
1 the string constant
2 the amplitude of the oscillation
3 the maximum velocity
4 the maximum acceleration
5 the period of oscillation
6 the frequency?

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Answers (6)

EmX
7 months ago
The first thing to note is that we have to convert all units to SI units.
  • EmX: Amplitude is the maximum displacement.
    This one mustn't be in SI unit.


    As for the next question we can't use the mass (300g) since it's obviously not what made the spring, to stretch the additional 10cm.

    So we need to find the additional force and add it to the initial mass to get the total mass that brought about the amplitude.

    See below for (b) and (c)
    Like 1    Dislike 0   7 months ago
  • EmX:
    Like 1    Dislike 0   7 months ago
  • EmX: Please be kind to point out any errors if you should notice them.
    Like 1    Dislike 0   7 months ago
  • 馃: pls how did u get the additional force (15) that was add to the additional 10cm in B
    Like 0    Dislike 0   2 months ago
  • EmX: It wasn't a force that was added.
    The question says
    "A spring stresses by 15cm when a mass of 300g is hang down from it, if the spring is then string is stressed additional 10cm"

    I think the person meant "Stretched" not "stressed", but it doesn't matter -- either way, we get the idea.
    Now, normally we probably wouldn't have needed to do that addition. But in the question, we are required to find the amplitude -- which is the maximum displacement of an object etc..

    Now with that in mind the spring was stretched 15cm and then an additional 10cm, meaning that the maximum displacement from point 'x' is 15+10=25cm

    Thus amplitude 25cm.
    馃槖
    Like 0    Dislike 0   2 months ago
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