A uniform rod AB, 100cm long and of mass 2kg is supported horizontally at points P and Q, 40cm and 65cm respectively from A. A mass of 1kg is hung at a point 25cm from A. If the rod is in equilibrium, calculate the reactions at the support(Take g= 10m/s²).?

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7 months ago

As we already know, when dealing with moments, it's always about the forces about a pivot.

And in the diagram below, The two arrows at P&Q represent the reactions at those pivots.

Therefore it is the value of P& Q we're looking for in this question.

Before we go any further we know in equilibrium

Sum of Upward forces equals sum of downward forces

In this case the upward forces are P &Q.

The downward forces are the mass of the ruler (2kg)and the 1kg mass attached at 25cm from A.

Observe below