### Calculate the total distance covered by a train before coming to rest if its initial...

Calculate the total distance covered by a train before coming to rest if its initial velocity is 30m/s with a constant retardation of 0.1m/s^2?

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EmX
3 weeks ago
Write out your parameters.
Note that it's retardation, thus it's negative.

And since it comes to rest out final velocity is Zero.
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HENRYVILLA
3 weeks ago
S = V^2−U^2/20

S = 0^2−30^2/2×0.1
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Malik
3 weeks ago
Total distance(s)=?

Final velocity=0 since the train is coming to rest.

Initial velocity=30m/s²

a=-0.1m/s²

V²=U²+2as

0²=30²+(2)(-0.1)(s)

-900=-0.2s

s=900/0.2

s=4500m or 4.5km.
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Dolly P
3 weeks ago
a=-0.1m/s2
u=30m/s
v=0
S=?

V2=U2+2aS
0=(30x30)+2(-0.1)xS
0=90-0.2S
-90=-0.2S
S=90/0.2
S=450m
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• Dolly P: Sorry,there is a mistake in the calculation

30x30=900 and not 90
so,
S=900/0.2
S=4500m
3 weeks ago
isaaq
3 weeks ago
s=?
u=30m/s
a=0.1m/s2
v=0
u2=u2+2as
0=(30*30)+2(0.1*s)
900+0.25=0
0.25=900
s=900/0.2
s=4500m
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PaulB
3 weeks ago
FIRST WE NEED TO FIND TIME
A=V2_V1/T
-0.1=0-30/T
T=-30/-0.1
T=300SECONDS

S=UT + ½aT²
s=30x300] + [-0.1x 90000]/2
s=9000 -4500= 4500METRES
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Aliyu
3 weeks ago
distance covered=speed/time =30/0.1=300m
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