Given that sin x=0.5, find d values of x between 90° and 360°?

Given that sin x=0.5, find d values of x between 90° and 360°?

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Answers (2)

AaCcTt
5 months ago
sin x=0.5
x=sin^-1(0.5)
x=30
it is only the 2nd quadrant(91-180) that sin is positive between 90&360
sin x=sin(180-x)
sin30=sin(180-30)
sin30=sin150
i.e x=150
isaaq
8 months ago
x is a 30º reference angle (from the x-axis)

sine is positive in quadrants I and II
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