Myschool CBT Challenge Season 6 - Cash Prize Of N200,000 To Be Won!

Show that X = 2 in the expression below 4^* + 3^* = 5^* Pls...

Show that X = 2 in the expression below
4^* + 3^* = 5^*
Pls note that * is X?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

JAMB 2020 CBT Mobile App - Download Now, It's Free!
JAMB 2020 CBT Software - Download Now, It's Free!

Answers (7)

4* + 3* = 5*
taking log of both sides
logx + logx = logx
4 3 5
making a change of base (all log carrier base 10)
logx + logx = logx
___ ___ ___
log4 log3 log5
log(x-4) + log(x-3) =log(x-5)
log(x-4+x-3) = log(x-4)
2x-7=x-5
2x-x=7-5
x=2
Robert Endurance
3 weeks ago
4^x + 3^x= 5^x
From Pythagorean triple principle,
the square of a number plus the square of another number should give a corresponding square of a new number.

So,
a^2 + b^2= c^2 is an illustration

Thus, relating the expression, 4^x + 3^x= 5^x to a^2 + b^2= c^2, x should automatically equals 2.

Thank you.
mhz vee
1 month ago
7^x = 5^x
mhizzlee
1 month ago
Why not just write
4^x + 3^x = 5^x
Hint: Perhaps you should check out the Pythagorean Theorem.
delibee
1 month ago
4^x + 3^x = 5^x
7^x = 5^x
i think this should be your answer.
no where to go again
  • Abdulazeez Suleiman: 4*+3*=5*
    taking log of both side
    logx + logx = logx
    4 3 5
    making a change of base (all log carries base 10)

    logx + logx = logx
    ___ ___ ___
    log4 log3 log5
    log(x-4) + log(x-3) = log(x-5)
    log(x-4+x-3) = log(x-5)
    2x-7=x-5
    2x-x=7-5
    x=2
    Like 0    Dislike 0   3 weeks ago
Ask Your Own Question

Quick Questions

See More Mathematics Questions
 
JAMB 2020 CBT Software Agents - Click Here to Apply
JAMB 2020 CBT Software - Download Now, It's Free!
JAMB 2020 CBT Mobile App - Download Now, It's Free!