two inductors of inductance 5 mH and 15mH are connected in series and a current of 5A flows through them.the total enegy stored in the inductors is?

A.250.0J

B.50.0

C 62.5J

D.500.0J?

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A.250.0J

B.50.0

C 62.5J

D.500.0J?

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delibee

5 months ago

5 months ago

C) 62.5J is the answer

The energy in an inductor is:

E = 1/2 x L x (i^2)

So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5m

The energy in an inductor is:

E = 1/2 x L x (i^2)

So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5m

peace

5 months ago

5 months ago

The answer is C.

The energy in an inductor is:

E = 1/2 x L x (i^2)

So in 5mH inductor: E = 0.5 x 5x10^-3 x

(5)^2 = 2.5x10^-3 x 25 = 62.5mJ

In the 15mH inductor it's 15/5 times more

or 187.5mJ

The energy in an inductor is:

E = 1/2 x L x (i^2)

So in 5mH inductor: E = 0.5 x 5x10^-3 x

(5)^2 = 2.5x10^-3 x 25 = 62.5mJ

In the 15mH inductor it's 15/5 times more

or 187.5mJ

EmX

5 months ago

5 months ago

The formula is E=½LI²

Since there are two inductors connected the series.

Inductors in series are simply “added together” because the number of coil turns is effectively increased, with the total circuit inductance Lₜ being equal to the sum of all the individual inductances added together.

See the remaining below

Since there are two inductors connected the series.

Inductors in series are simply “added together” because the number of coil turns is effectively increased, with the total circuit inductance Lₜ being equal to the sum of all the individual inductances added together.

See the remaining below

Malik

5 months ago

5 months ago

The answer is C.

Explanation

The energy in an inductor is:

E = 1/2 x L x (i^2)

So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5mJ

In the 15mH inductor it's 15/5 times more or 187.5mJ

Explanation

The energy in an inductor is:

E = 1/2 x L x (i^2)

So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5mJ

In the 15mH inductor it's 15/5 times more or 187.5mJ

5 months ago

The energy in an inductor is:

E = 1/2 x L x (i^2)

So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5mJ

In the 15mH inductor it's 15/5 times more or 187.5mJ