two inductors of inductance 5 mH and 15mH are connected in series and a current...

two inductors of inductance 5 mH and 15mH are connected in series and a current of 5A flows through them.the total enegy stored in the inductors is?
A.250.0J
B.50.0
C 62.5J
D.500.0J?

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Answers (8)

isaaq
1 week ago
The answer is C.
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more or 187.5mJ
ogborpaul
1 week ago
62.5j
delibee
1 week ago
C) 62.5J is the answer
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5m
mizta smart
1 week ago
The answer is C.
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x
(5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more
or 187.5mJ
EmX
1 week ago
The formula is E=½LI²

Since there are two inductors connected the series.
Inductors in series are simply “added together” because the number of coil turns is effectively increased, with the total circuit inductance Lₜ being equal to the sum of all the individual inductances added together.

See the remaining below
  • EmX: as you can seee the answer is not in the option. And I'm certain I didn't make a mistake.


    the question is wrong.
    If I were to rephrase it this way

    Two inductors of inductance 5H and 15H are connected in series and a current of 5A flows through them.the total enegy stored in the inductors is?
    Like 0    Dislike 0   1 week ago
Malik
1 week ago
The answer is C.
Explanation
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more or 187.5mJ
Gaby
1 week ago
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x
(5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more
or 187.5mJ
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