### two inductors of inductance 5 mH and 15mH are connected in series and a current...

two inductors of inductance 5 mH and 15mH are connected in series and a current of 5A flows through them.the total enegy stored in the inductors is?
A.250.0J
B.50.0
C 62.5J
D.500.0J?

To get notifications when anyone posts a new answer to this question,

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

EmX
1 year ago
The formula is E=½LI²

Since there are two inductors connected the series.
Inductors in series are simply “added together” because the number of coil turns is effectively increased, with the total circuit inductance Lₜ being equal to the sum of all the individual inductances added together.

See the remaining below
Follow
• EmX: as you can seee the answer is not in the option. And I'm certain I didn't make a mistake.

the question is wrong.
If I were to rephrase it this way

Two inductors of inductance 5H and 15H are connected in series and a current of 5A flows through them.the total enegy stored in the inductors is?
1 year ago
• Vek Tor: Damn!!...So correct
6 months ago
ogborpaul
1 year ago
62.5j
Follow
delibee
1 year ago
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5m
Follow
isaaq
1 year ago
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more or 187.5mJ
Follow
• Vek Tor: U aren't getting the question huh....Find the TOTAL ENERGY!!
6 months ago
mizta smart
1 year ago
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x
(5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more
or 187.5mJ
Follow
Malik
1 year ago
Explanation
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x (5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more or 187.5mJ
Follow
Gaby
1 year ago
The energy in an inductor is:
E = 1/2 x L x (i^2)
So in 5mH inductor: E = 0.5 x 5x10^-3 x
(5)^2 = 2.5x10^-3 x 25 = 62.5mJ
In the 15mH inductor it's 15/5 times more
or 187.5mJ
Follow