A circle of radius 28cm is opened to form a square. What is the maximum possible area of the chord?

#### Post an Answer

#### Answers (4)

Ask Your Own Question
#### Quick Questions

See More Mathematics Questions

To get notifications when anyone posts a new answer to this question,

Follow New Answers

Follow New Answers

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

HENRYVILLA

10 months ago

10 months ago

The area of the original sheet = (pi)r^2 = (22/7)*196 = 616 sq cm.

The area of the 2 small circles cut out = 2*(pi)r^2 = 2(22/7)*3.5^2 = 77 sq cm.

The area of the remaining sheet = 616–77 = 539 sq cm.

The area of the 2 small circles cut out = 2*(pi)r^2 = 2(22/7)*3.5^2 = 77 sq cm.

The area of the remaining sheet = 616–77 = 539 sq cm.

delibee

10 months ago

10 months ago

The area of the original sheet = (pi)r^2 = (22/7)*196 = 616 sq cm.

The area of the 2 small circles cut out = 2*(pi)r^2 = 2(22/7)*3.5^2 = 77 sq cm.

The area of the remaining sheet = 616–77 = 539 sq cm.

The area of the 2 small circles cut out = 2*(pi)r^2 = 2(22/7)*3.5^2 = 77 sq cm.

The area of the remaining sheet = 616–77 = 539 sq cm.

10 months ago

MY point is, a chord is simply a straight line, It doesnt have an area. In that case, i'll have to assume that you mean't.

A circle of radius 28cm is opened to form a square. What is the maximum possible area of the Square.

see below.

First of all, you can't really use a circle to build a square, unless you first of all draw the square in the circle, then cut it.

With that imagination now, let us soolve this question.

NB. All sides of the square are equal.

The diameter is D=2r

D=28x2=56cm

The principle to solving this question is that for the square to be at maximum fit, the diagonal must be equal to the diameter of circle.

from the diagonal we can find the Other sides of the square, using pythagoras theorem +.

see image below to get full understanding.