### A conductor of length 5m carrying a current of 15A is placed in a uniform...

A conductor of length 5m carrying a current of 15A is placed in a uniform magnetic field of flux density 0 25T. If the conductor is placed at 60° to the field then the force on it is?

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equation
Force (N) = magnetic flux density (T) * current (A) * length (m)
OR in short
F = B I L.
THEREFORE:
B= 0.25T
I= 15A
L= 5M
F=?
:. F= 0.25*15*5
= 18.75N.
delibee

delibee
7 months ago
equation
Force (N) = magnetic flux density (T) * current (A) * length (m)
OR in short
F = B I L.
THEREFORE:
B= 0.25T
I= 15A
L= 5M
F=?
:. F= 0.25*15*5
= 18.75N.
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Gaby
7 months ago
Force (N) = magnetic flux density (T) *
current (A) * length (m)
OR in short
F = B I L.
THEREFORE:
B= 0.25T
I= 15A
L= 5M
F=?
:. F= 0.25*15*5
= 18.75N.
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EmX
7 months ago
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