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Show that the pressure of a gas is equal to 2/3 of the total translation...

Show that the pressure of a gas is equal to 2/3 of the total translation kinetic energy of the molecules in a unit volume?

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Answers (3)

3 weeks ago
3 weeks ago
PV=nRT for ideal gas.
Translational KE=3/2*nRT
Translational KE=3/2 * PV for ideal gas.
(P+an²/v²)(v-nb) = nRT for real gas
For real gas, KE =(p+an²/v²)(v-nb) *3/2
  • isaaq: Or
    The product of pressure and volume per mole is proportional to the average (translational) molecular kinetic energy.
    K.E.= KT
    P is pressure.
    V is volume per mole
    K is a constant
    T is temperature.
    Like 1    Dislike 1   3 weeks ago
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