pls make n the subject of the formula in:

s=n/2[2a+(n-1)d]?

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s=n/2[2a+(n-1)d]?

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1 month ago

Swap the d and the (n-1)Remove the inner parentheses on the right by distributing:

Remove the remaining parentheses on the right by distributing:

Get 0 on the left by subtracting 2s from both sides:

Swap sides:

Rearrange the terms in descending order Factor n out of the two terms in the middle:

Swap the n and the (2a-d)We use the quadratic formula.

Since there is already a letter "a", we will use capital letters to avoid conflict of notation:

Ax2 + Bx + C = 0 has solution

x = n, A = d, B= (2a-d), C = -2s